• crayzeesheep

• in reply to: Multiple Select User Field and update_field()
• September 27, 2017 at 9:00 am

I just have a quick follow-up question to this original question, and didn’t want to clutter the forum with additional posts. If I should make an additional post, please let me know.

So everything is working perfectly fine up until this point. I am able to add and remove Users as I please, so long as the User Field is initially populated in the Post.

However, when using a Multiple Select User Field, if no User is initially populated in the Post, and the following command is run:

$test = get_field('cb_roster', false, false);
print_r($test);

This returns nothing at all. Therefore, if I use something like:
array_push($test, $current_user);

Nothing will happen (since it doesn’t exist).

So, if I run the following:

$current_user = get_current_user_id();
$current_user = strval($current_user); //converting to string just in case

$test = get_field('cb_roster', false, false);
$current_user = array($current_user);
print_r($test);
print_r($current_user);

update_field('cb_roster', $current_user);

And then run:

$test = get_field('cb_roster', false, false);
print_r($test);

I get a blank value (as though it does not exist).

The output for print_r($current_user) returns:
Array ( [0] => 24 )

Which matches the format of the Array if it were populated from the Post.

Any input is greatly appreciated!

• crayzeesheep

• in reply to: Multiple Select User Field and update_field()
• September 26, 2017 at 3:30 am

I got it… Turns out I was thinking too hard…

I re-read the documentation for get_fields().

Answer was that I don’t need to provide the full array as I was doing. Instead, the answer was to return ‘cb_roster’ like so:

$roster = get_fields('cb_roster', false, false);
print_r($roster);

Which returns the array without formatting. The array without formatting looks like this:

Array([0]=>24)

Therefore, I only need to pass this script:

$value = '21';

  array_push($roster, $value);
  update_field('cb_roster', $roster);

Sorry for the confusion…

• crayzeesheep

• in reply to: Multiple Select User Field and update_field()
• September 26, 2017 at 3:08 am

Okay, here’s the ultimate test in my opinion, and I have it narrowed down to my approach being completely wrong. The only problem is, I don’t know why it’s wrong?

If I run:

$roster = get_field('cb_roster');
print_r($roster);

update_field('cb_roster', $roster);

And then after that script runs, I check the field:

$roster = get_field('cb_roster');
print_r($roster);

I get the output:
Array ()

What am I missing? To me, this is like being handed a box with a ball inside. I open the box, put the ball on the table. I put the ball back in the box, and now the box is empty…

Any help is greatly appreciated.

• crayzeesheep

• in reply to: Multiple Select User Field and update_field()
• September 26, 2017 at 12:01 am

My apologies, I knew in my wall of text I would omit things. That code in its entirety is actually –

  $value = '21';

  // format value
  if( !$value || $value == 'null' )
  {
    return false;
  }

  // temp convert to array
  $is_array = true;

  if( !is_array($value) )
  {
    $is_array = false;
    $value = array( $value );
  }

  foreach( $value as $k => $v )
  {
    $user_data = get_userdata( $v );

    //cope with deleted users by @adampope
    if( !is_object($user_data) )
    {
      unset( $value[$k] );
      continue;
    }

    $value[ $k ] = array();
    $value[ $k ]['ID'] = $v;
    $value[ $k ]['user_firstname'] = $user_data->user_firstname;
    $value[ $k ]['user_lastname'] = $user_data->user_lastname;
    $value[ $k ]['nickname'] = $user_data->nickname;
    $value[ $k ]['user_nicename'] = $user_data->user_nicename;
    $value[ $k ]['display_name'] = $user_data->display_name;
    $value[ $k ]['user_email'] = $user_data->user_email;
    $value[ $k ]['user_url'] = $user_data->user_url;
    $value[ $k ]['user_registered'] = $user_data->user_registered;
    $value[ $k ]['user_description'] = $user_data->user_description;
    $value[ $k ]['user_avatar'] = get_avatar( $v );

  }

  // de-convert from array
  if( !$is_array && isset($value[0]) )
  {
    $value = $value[0];
  }

Sorry about that.

So this was my code, but my issue from before still stands. I wouldn’t be able to output the array of $value and check the types using gettype as I previously mentioned if this was not the case.

I updated my original post to reflect this, so it’s not confusing to someone reading it for the first time. Thanks!