the_field php problem

• jadestein

• August 8, 2018 at 10:46 pm

This work:
<?php
$urlyt = ‘QK-Z1K67uaA’;
$url = ‘https://www.googleapis.com/youtube/v3/videos?part=snippet&id=&#8217;. $urlyt .’&keysecret’;
?>
output: https://www.googleapis.com/youtube/v3/videos?part=snippet&id=QK-Z1K67uaA&keysecret
this doesn’t work:
<?php
$urlyt = the_field(‘ytvideo’);
$url = ‘https://www.googleapis.com/youtube/v3/videos?part=snippet&id=&#8217;. $urlyt .’&keysecret’;
?>
output: QK-Z1K67uaA

Why is there such a mistake

• jadestein

• August 8, 2018 at 10:58 pm

I used ‘get_field’ problem solved .