Hi There, I am new to using this, so please bear with me. I have 3 fields that I only want displayed in a post if they are checked or equal to True. The fields are:
screened_porch
bed_linens_provided
fireplace
I have the post code as:
<?php echo get_field(‘screened_porch’); ?>
<?php echo get_field(‘bed_linens_provided’); ?>
<?php echo get_field(‘fireplace’); ?>
Right now if the check box is selected, a 1 shows on the post. I want it so that the field shows up i.e.: screened_porch or its label “Screened Porch” shows up. Any help is greatly appreciated. Thanks so much. -Beth
Hi Beth.
Well, if you validate it with a simple if, something like this:
<?php if ( get_field('fireplace' ) ) : ?>
// do something
<?php the_field('fireplace'); ?>
<?php endif; ?>
This will show the field only if the field “fireplace” have something, this works with text fields and any field as well.
Here the docs about it https://www.advancedcustomfields.com/resources/true-false/
Like a extra point. To print the value of a custom field, you can use directly the function the_field('your_field_name') but if do you want to check or save the value of the field in a variable, you can use get_field('your_field_name')
Hi There, I am starting to understand this, but I am not quite there yet. I have a test post at:
https://www.barakaentodos.com/wp/test/
Where I checked:
screened_porch
bed_linens_provided
fireplace
and it displays out:
// do something 1 // do something 1 // do something 1
If the do something could be replaced with the field label or:
Screened Porch
Bed Linens Provided
Fireplace
that would be ideal, but I am not quite sure how to do that?
To display the label of the field you need to get the field object. There is an example of showing a field label on this page https://www.advancedcustomfields.com/resources/get_field_object/
