Hello there!
In a custom post I specify a date thanks to ACF.
I need to compare that field to the current date. If that field is in future I want to show “Soon”.
That is my current code :
<?php
$today = date("Y-m-d");
echo $today;
$date_fr = get_field('date_de_sortie_fr', false, false);
$date_fr = new DateTime($date_fr);
?>
<span><?php echo $date_fr->format('Y-m-d'); ?></span>
I think that my today date is not in a good format to do the comparison. Do you confirm ?
Also, how to compare that dates ? Can you help me please ?
Try this, using DateTime() rather than date():
<?php
$today = new DateTime();
$date_fr = DateTime::createFromFormat('Ymd', get_field('date_de_sortie_fr'));
?>
<span>
<?php
if($date_fr > $today) echo "Soon: ";
echo $date_fr->format('Y-m-d');
?>
</span>
NOTE This requires that you store the date field in Ymd format.
This should work:
<?php
$endOfDay = strtotime("tomorrow") - 1;
$unixtimestamp = strtotime(get_field('date_de_sortie_fr'));
$date_fr = date("Y-m-d", $unixtimestamp);
echo $unixtimestamp > $endOfDay ? "soon" : $date_fr;
EDITED: Syntax Error
Thank you!!
The first solution solved my issue.
Just for information the second didn’t…
Oh, did you see the missing ; at the end of $date_fr = date("Y-m-d", $unixtimestamp)? :D… sorry. If you´re working with Date Picker field, this should also works fine :).
I didn’t, but i’ll try to confirm your code 😉.
Thank you again!
