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If True do this / False do that

  • What I would like to achieve is if True is ticked, display X content. Otherwise, display Y content. And currently, I’ve gotten up to this point:

    <?php if ( get_field('true_false_box') == true ) { ?>
    
    			Display X content
    
    			<?php } else { ?>
    
    Display Y content
    
    <?php } ?>

    Problem I’m facing now is both tick / untick the True/False checkbox displays only the Y content. However, the var_dump reports the true / false status correctly.

  • I don’t necessarily see any errors in that code but you don’t have to do == true. Make sure you have the right field name and you are testing on a post/page that has content in there.

    You can also improve/clean up your code a bit. The code below is very readable but be careful not to use it too much or you wont easily see which endif belongs to which if.

    <?php if ( get_field( 'field_name' ) ): ?>
    
    This is displayed when the field_name is TRUE or has a value.
    
    <?php else: // field_name returned false ?>
    
    This is displayed when the field is FALSE, NULL or the field does not exist.
    
    <?php endif; // end of if field_name logic ?>
  • I used your code, Tim and am getting this PHP error:

    Error while parsing PHP: syntax error, unexpected 'else' (T_ELSE)

    my code:

    				<?php if ( get_field( 'btn_show' ) ); ?>
    				<p class="text-center"><a class="btn" href="<?php the_sub_field('btn_url'); ?>"><?php the_sub_field('btn_text'); ?></a></p>
    				<?php else: // field_name returned false ?>
    
    				<?php endif; // field_name ?>
  • Hey tigre. Your if ( get_field( 'btn_show' ) ); should be if ( get_field( 'btn_show' ) ):.

    The semicolon (;) ended the line so that’s why your else was “unexpected” according to PHP.

  • Hi, I don’t seem to be able to get this working using the following:

    <?php if ( get_field( 'featured' ) ): ?>
    <div class="featured">
    <?php else: ?>
    <div class="not-featured">
    <?php endif; ?>

    <div class="not-featured"> Is outputted if the featured True/False field is checked or not.

    Any ideas what I’m doing wrong?

    Cheers.

  • You could start by dumping the raw data that get_field gets for you and see if that matches your expectations in various scenerio’s (checked, unchecked, field not existing).

    I use a snippet like this to dump things (because I don’t like how var_dump() looks):

    echo "<pre style=\"text-align:left;padding:10px;border:1px solid red;background-color:#fff;color:#111;font-family:Courier;\">";
    print_r( get_field( 'featured' ) );
    echo "</pre>";
  • I used this withe the true/false Field Type :

    $true = get_post_meta( get_the_ID(), 'true_false', true );
    
    if ( $true == '1' ) {
    
        // Do Something
    
    }
  • Try this code. Make sure to add the #hide_this_div to the whatever you want to hide:

    add_action('template_redirect', 'hide_disabled_blocks');
    
    function hide_disabled_blocks() {
    	global $post;
    	
    	// get dynamic project id
        $post_id = $post->ID;
    	
    	// get value of true-false field in each post
    	$hidediv = get_post_meta($post_id, 'ACF-field-name', true);
    	
    	if is_singular( 'post' ) :?>
    	
    	<style type="text/css">
    		<?php
    		
    		// if "ACF true-false command" is false, hide the Div ID
    		if  ( ($hidediv == '0') || (empty($hidediv)) ): ?>
    			#hide_this_div { display: none; }
    		<?php endif;
    		
    		?>
    	</style>
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