What I would like to achieve is if True is ticked, display X content. Otherwise, display Y content. And currently, I’ve gotten up to this point:
<?php if ( get_field('true_false_box') == true ) { ?>
Display X content
<?php } else { ?>
Display Y content
<?php } ?>
Problem I’m facing now is both tick / untick the True/False checkbox displays only the Y content. However, the var_dump reports the true / false status correctly.
I don’t necessarily see any errors in that code but you don’t have to do == true. Make sure you have the right field name and you are testing on a post/page that has content in there.
You can also improve/clean up your code a bit. The code below is very readable but be careful not to use it too much or you wont easily see which endif belongs to which if.
<?php if ( get_field( 'field_name' ) ): ?>
This is displayed when the field_name is TRUE or has a value.
<?php else: // field_name returned false ?>
This is displayed when the field is FALSE, NULL or the field does not exist.
<?php endif; // end of if field_name logic ?>
I used your code, Tim and am getting this PHP error:
Error while parsing PHP: syntax error, unexpected 'else' (T_ELSE)
my code:
<?php if ( get_field( 'btn_show' ) ); ?>
<p class="text-center"><a class="btn" href="<?php the_sub_field('btn_url'); ?>"><?php the_sub_field('btn_text'); ?></a></p>
<?php else: // field_name returned false ?>
<?php endif; // field_name ?>
Hey tigre. Your if ( get_field( 'btn_show' ) ); should be if ( get_field( 'btn_show' ) ):.
The semicolon (;) ended the line so that’s why your else was “unexpected” according to PHP.
Hi, I don’t seem to be able to get this working using the following:
<?php if ( get_field( 'featured' ) ): ?>
<div class="featured">
<?php else: ?>
<div class="not-featured">
<?php endif; ?>
<div class="not-featured"> Is outputted if the featured True/False field is checked or not.
Any ideas what I’m doing wrong?
Cheers.
You could start by dumping the raw data that get_field gets for you and see if that matches your expectations in various scenerio’s (checked, unchecked, field not existing).
I use a snippet like this to dump things (because I don’t like how var_dump() looks):
echo "<pre style=\"text-align:left;padding:10px;border:1px solid red;background-color:#fff;color:#111;font-family:Courier;\">";
print_r( get_field( 'featured' ) );
echo "</pre>";
I used this withe the true/false Field Type :
$true = get_post_meta( get_the_ID(), 'true_false', true );
if ( $true == '1' ) {
// Do Something
}
Try this code. Make sure to add the #hide_this_div to the whatever you want to hide:
add_action('template_redirect', 'hide_disabled_blocks');
function hide_disabled_blocks() {
global $post;
// get dynamic project id
$post_id = $post->ID;
// get value of true-false field in each post
$hidediv = get_post_meta($post_id, 'ACF-field-name', true);
if is_singular( 'post' ) :?>
<style type="text/css">
<?php
// if "ACF true-false command" is false, hide the Div ID
if ( ($hidediv == '0') || (empty($hidediv)) ): ?>
#hide_this_div { display: none; }
<?php endif;
?>
</style>
