Hi,
I use a ACF custom field on a custom taxonomy. I want to get the label of the selected checkbox from the acf field “book_type” and use it in a $variable.
If i use this code, it shows the name of the custom field but not the label, like this: “non_fiction” instead I want to show the label which is called: “Non Fiction”
<?php the_field('book_type', $term); ?>
Also I like to use it as a variable instead of echoing directly. So I tested all code I could find with google, like this for example:
$field = get_field_object('field_name');
$value = get_field('field_name');
$label = $field['choices'][ $value ];
?>
<p>Color: <?php echo $label; ?></p>
But none of them does the job, how can I get the label of a taxonomy checkbox field with ACF?
Just to make sure that I understand.
You have set up a checkbox field with choices something like:
value_1 : Label 1
value_2 : Label 2
value_3 : Label 3
and you want to echo label on the front end rather than the value.
Do you use the value on the front end or just the label?
Yes exactly as you describe. I want to use the Label (front end) in a variable instead of the value. I have tried all code I could find available on the internet, but I didn’t get it working, hope you can help me?
$values = get_field('checkbox_field');
$field = get_field_object('checkbox_field');
$choices = $field['choices'];
foreach ($choices as $value => $label) {
if (in_array($choice, $values)) {
echo 'LABEL: ',$label,': VALUE',$value,'<br />';
}
}
Hi John,
I get this error when using your code:
Warning: Invalid argument supplied for foreach() in ... on line 83
I used the name of my field: book_type where you used checkbox_field.
Does it matter that it is a field used on a custom taxonomy? Not on a post.
There are two likely causes of this. First is that your field does not have any choices. 2 is that you are using the value outside of the loop. Are you trying to show the selected values for a post or are you trying to show them before the posts are listed?
could you try if this works:
$book_type ='';
$book_type_field = get_field_object('book_type');
$book_type_values = get_field('book_type');
$count = count($book_type_values);
foreach ($book_type_values as $key => $value) {
$book_type .= $book_type_field['choices'][ $value ];
if (($count - 1 - $key) >= 1){$book_type .= ', ';}
}
echo $book_type; //do this whenever you wish (this variable should contain all chosen labels, separated by a comma)
or do you get also a error with this code
