Gallery field don't work in frontend as a sub_field of a Repeater

• Boniz

• September 10, 2013 at 7:16 am

I can’t show in frontend the gallery field I’ve created on a sub_field of a Repeater.

I use this code:

<?php
				// Create the Markup for the Custom Gallery
				$images = the_sub_field('galleria_pianta');
				if($images): ?>
				
				<div id="ok_gallery">
				<?php foreach( $images as $image ): ?>
					<a class="lightbox" data-fancybox-group="gallery-<?php the_ID(); ?>" title="<?php echo $image['title']; ?> <?php echo $image['description']; ?>" href="<?php echo $image['url']; ?>">
						<img src="<?php echo get_template_directory_uri(); ?>/img/load.gif" data-src="<?php echo $image['sizes']['thumbnail']; ?>" data-src-retina="<?php echo $image['sizes']['thumbnail']; ?>" alt="<?php echo $image['alt']; ?>" />
						<?php echo $image['title']; ?>
					</a>
				<?php endforeach; ?>
				<div class="clearfix"></div>
				</div>
				
				<?php endif; ?>

I get two error ( “2” like the number of the image in the gallery ) like this:

Notice: Array to string conversion in /Applications/MAMP/htdocs/nm/wp-content/plugins/advanced-custom-fields/core/api.php on line 610

• Elliot

• September 10, 2013 at 11:01 am

Hi @Boniz

I believe the issue is due to misusing the the_sub_field function.

Your first line of code should be changed to:

$images = get_sub_field('galleria_pianta');

So, to clarify, please use get_sub_field to get data.

Thanks
E

• effect

• October 16, 2013 at 10:35 pm

Getting the exact same error but from a much simpler sub field usage, I’m sure its just something I’m not writing out correctly:

<?php if( get_field('slide') ): ?>
	<?php while( has_sub_field('slide') ): ?>
		<?php the_sub_field('slide_image'); ?>
		<?php the_sub_field('slide_title'); ?>
		<?php the_sub_field('slide_subtitle'); ?>
	<?php endwhile; ?>
<?php endif; ?>

• Elliot

• October 17, 2013 at 4:35 pm

Hi @elliot

The error in question (array to string conversion) is self explanatory. One of the values for your sub fields is actually an array. Most likely the image sub field.

You can echo an array in PHP, that just doesn’t work.

So instead, you need to read the docs and use get_sub_field instead to correctly render out the HTML you want.

Thanks
E