Displaying a field that is conditional to another

• cezilia_mar

• June 28, 2017 at 2:15 pm

Hey guys, new to ACF. First of all, sorry if this has been answered before. I haven’t been able to find it.

I have a couple of custom fields on a custom post type which are conditional to another:

I have “brands” wich is a select with a list of brands
and then “brandA-models”, “brandB-models”, “brandB-models” etc which are a select of models for each brand and depend on what was selected as brand. On Back-end they work perfect. What I dont know how to do is display this info on the post.

I don’t need this to be dinamical, it’s more of a tech-sheet which lists brand-model-etc

I have tried this but doesn’t work (my php it’s beginners level at best, i know):

 <li>Brand: <strong><?php the_field('brand') ?></strong></li>
                <li>Model: <strong> <?php

                    $brand = get_field('brand');
                    $modelo_brand = "modelo_" . $brand;
                    
                    
    
                    if(get_field('marca'))
                    {
                        echo '' . get_field('$modelos_marca') . '';
                    }

                    ?></strong></li>

Could someone please point me in the right direction?

Thanks!!

• markbloomfield

• July 5, 2017 at 10:20 pm

Hi @cezilia_mar

Not sure if I’m understanding your query, however the 1 problem I can see in your code is this: get_field('$modelos_marca')

If you’re fetching a variable, you can drop the quotes so that it becomes: get_field($modelos_marca)

So your code might be:

$brand = get_field('brand');
$modelo_brand = "modelo_" . $brand;

if(get_field('marca')) {
  echo get_field($modelo_brand);
}

Alternatively, perhaps you could clarify your problem?

• cezilia_mar

• July 7, 2017 at 12:56 pm

Yes I definitely think the code I wrote wont work.

What I need is to display a field that has conditional logic to another.
I have a list of brands and models. To display brand is easy I just use <?php the_field(‘brand’) ?>

Now to display a model that has a conditional logic to that brand, that is when I find myself in trouble.

With your help I managed echo the name of the field.

<?php
$brand = get_field(‘brand’);
$model = “model_”;
$model_brand = $model . $brand;

echo $model_brand;

?>

What I need is a way to use this stored in the new variable “model_brand” to get the field “model_brand” to give you an example the field could be named “model_ford”. I am not sure this is the right path, probably not. But I imagine there has to be a way to display a field with conditional logic, right?

• markbloomfield

• July 7, 2017 at 5:33 pm

So

1) you need to fetch the name of the brand, ie ford or bmw and you currently do this with $brand = get_field('brand');

2) you then need to fetch the models using this brand variable and your naming structure is model_$brand essentially. to do this you’d then say $models = get_field('model_'.$brand);

Have you tried this?

What do you see if you try do print_r($models) ?