Is it possible to display a specific repeater field row, and only one row, depending on the date specified in a sub field date field?
The following works to display all the rows greater than $today. If there are 10 rows greater than $today all 10 rows display. If 3 rows are greater than $today, all 3 rows display.
if( have_rows('surprise_item') ) {
$today = date('Ymd'); // define today's date
while ( have_rows('surprise_item') ) : the_row();
// date starting the week of surprise
$startweek = get_sub_field('date');
$bag_weeKstart = date_create($startweek);
$endweek = strtotime($startweek);
$endweek = strtotime("+7 day", $endweek);
$endweek = gmdate('Ymd', $endweek );
$bag_weeKend = date_create($endweek);
if( ($today <= $startweek) && ($today <= $endweek) ) { ?>
<h1>From <?php echo date_format($bag_weeKstart, 'M j, Y'); ?> to <?php echo date_format($bag_weeKend, 'M j, Y'); ?> your surprise is</h1>
<h2><strong>Toddler:</strong> <?php the_sub_field('toddler'); ?></h2>
<h2><strong>Baby:</strong> <?php the_sub_field('baby'); ?></h2>
<?php } ?>
<?php endwhile; //end of repeater rows ?>
<?php } else {
// show if no surprise defined
} // end repeater rows
Is it possible to display just one row – the first row based off a defined date field?
Add a break statement after showing the first. Example:
if (have_rows('repeater')) {
while (have_rows('repeater')) {
the_row();
if ($condition) {
// display row
// exit loop so no more are shown
break;
}
}
}
