Display only one Flexible Content Field at random

• Phil_Hart

• January 13, 2014 at 9:12 pm

Is there a way to randomly pick a single duplicate of a Flexible Content Field to display, so each time the user refreshes his/her page they’re presented with a unique set of data?

I’m guessing this may be down to some form of PHP but I’m not sure about where to start.

Many thanks in advance for any help or suggestions!
Phil

• Will

• January 14, 2014 at 1:40 am

Hi @Phil_Hart,

This code samples for getting a random repeater item should help: http://www.advancedcustomfields.com/resources/field-types/repeater/#wpshdo_4

• Elliot

• January 14, 2014 at 9:16 am

Hi guys

Yes, the repeater field example can also be used for the flexible content field!

Thanks
E

• Phil_Hart

• January 14, 2014 at 9:57 pm

Brilliant, thanks a lot guys!

Much obliged!

• AC

• February 17, 2015 at 11:44 pm

I would like to present an alternative solution as the one marked above didn’t work for me. This is how i did it, since i needed to keep the while loop and had to use get_sub_field();

Hope anyone can find it useful.

$flexible_row_number = 1;

//Count rows
$flexible_row_count = count( get_field("flexible_content_field_name") );
//Create random number out of number of rows. 
$flexible_row_rand = rand(1, $flexible_row_count);

// check if the flexible content field has rows of data
if( have_rows('flexible_row_flexible') ):

     // loop through the rows of data
    while ( have_rows('flexible_row_flexible') ) : the_row();

		//check if flexible row number equals random row number. 
		if ( $flexible_row_number == $flexible_row_rand ):
			if( get_row_layout() == "layout"):
			endif;
                        //If they do equal, add 1 to $flexible_row_number;
			$flexible_row_number++;
		else :
			//If they dont equal, add 1 to $flexible_row_number;
			$flexible_row_number++;
		endif;
	endwhile;
endif;