Date Picker – Code Syntax PHP

• andytc

• April 13, 2021 at 5:41 am

I have a working template file that has the date hardcoded as shown below –

$spring_date_end = strtotime($key."-04-01");

I want to insert the value of the date picker (from an options page) to replace this section of code “-04-01”

The date pickers are set to the Return Format= /m/d/

the_field('spring_term_dates_start' , 'options');

The fields are returning the date on the front end as= /01/04

current fields I have in place

spring_term_dates_start
spring_term_dates_end
summer_term_dates_start
summer_term_dates_end
autumn_term_dates_start
autumn_term_dates_end

Sample code section –

// My section of working code
// $key = $year

$result = array();
      
      foreach($posts_by_year as $key => $year){
                
        foreach($year as  $y){
          
          $date = strtotime($y['date']);
          list($ny,$nm,$nd) = explode('-',$y['date']);

          $spring_date_start = strtotime($key."-01-04");
          $spring_date_end = strtotime($key."-04-01");

          if($date >= $spring_date_start && $date <= $spring_date_end){
            $Season = 'Spring';
          }

          $summer_date_start = strtotime($key."-04-02");
          $summer_date_end = strtotime($key."-08-31");
          
          if($date >= $summer_date_start && $date <= $summer_date_end){
            $Season = 'Summer';
          }

          $autumn_date_start = strtotime($key."-09-01");
          $autumn_date_end = strtotime(($key+1)."-01-03");

          if($date >= $autumn_date_start && $date <= $autumn_date_end){
            $Season = 'Autumn';
          }
          
          if($nm == '01' && in_array($nd,array('01','02','03'))){
            $Season = 'Autumn';
          }

          $result[$key][$Season][$y['term']][] = $y;

        }

      }

I can’t work out how to replace the hardcoded date with the date picker field value whilst including the $key. ?