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count get_row_layout to add odd / even class

  • Hi,

    I am using flexible content with several layouts. Is there a way to count the number of a specific layout?

    For example, I have a layout called staff_member which contains several fields. I want to know how many staff_member layouts there are so I can add a class of odd or even to a div with class of “staff”. Or maybe there’s a more simple way to add a class of odd or even. CSS nth formatting doesn’t work because staff members divs are interrupted by department title divs.

    Here is the page:


    /* Staff Custom Fields
    ------------------------------------------------------------ */
    function wnd_staff()	{
    // check if the flexible content field has rows of data
    if( have_rows('staff_content') ): ?>
        	<div class="staff-content">
        <?php  // loop through the rows of data
        while ( have_rows('staff_content') ) : the_row();
            if( get_row_layout() == 'staff_member' ): // start staff row ?>
    			<div class="staff">
    				<div class="swrap">
    	        	<?php if( get_sub_field ('name')): // get staff name ?>
    	        	<h3><?php the_sub_field('name'); ?></h3>
    	        	<?php endif; ?>
    				</div><!-- end swrap -->
    		<?php elseif( get_row_layout() == 'department_layout' ): //start department row ?>
    			<div class="dep">
    	        	<?php if( get_sub_field ('department')): // get dep head ?>
    				<h2><?php the_sub_field('department'); ?></h2>
    				<?php endif;
    	        	if( get_sub_field('department_text') ): // get dep text
    				endif; ?>
           <?php endif;
        endwhile; ?>
            	</div><!-- end staff-content -->
    <?php else :
        // no layouts found
  • Because you have different types of layouts the solution would be to keep a running total of each type of layout.

    $layout_counts = array();
    // ... some time later
    while (have_rows('staff_content')) {
      $layout = get_row_layout();
      if (!isset($layout_counts[$layout])) {
        $layout_counts[$layout] = 0;
      $class = 'even';
      if ($layout_counts[$layout] % 2) {
        $class = 'odd';
      //... some time later
      if ($layout == 'staff_member') {
          <div class="staff <?php echo $class; ?>">
             /// etc...
  • Thanks John. That’s exactly what I needed.

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