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  • Hi @tanK

    Your code contains a few errors:

    1. You have selected a return type of ID on the image field. This will cause $product[‘product_image’] to contain and ID of the image

    2. Your code references $product[‘sizes’][‘product_image’], but this will never exist. The image ID will sit at $product[‘product_image’]. This is an ID, not a URL

    I think what you want to do is set the image return type to ‘Image Object’, then use this code:

    echo '<img src=”'.$product['product_image']['sizes']['product_image'].'”>';