Reply To: Displaying a field that is conditional to another

• markbloomfield

• July 5, 2017 at 10:20 pm

Hi @cezilia_mar

Not sure if I’m understanding your query, however the 1 problem I can see in your code is this: get_field('$modelos_marca')

If you’re fetching a variable, you can drop the quotes so that it becomes: get_field($modelos_marca)

So your code might be:

$brand = get_field('brand');
$modelo_brand = "modelo_" . $brand;

if(get_field('marca')) {
  echo get_field($modelo_brand);
}

Alternatively, perhaps you could clarify your problem?