How to out put last row only ; While~endwhile

• labzz

• April 13, 2022 at 7:06 am

            while ( ( have_rows('visits_range', 'option') == 'use') ) : the_row();
                $usage = get_sub_field('usage');
                $limits = get_sub_field('limits');
                if( get_row_layout() == 'item' && ($usage == 'yes') && ($visits > $limits) ):
                    $limits = get_sub_field('limits');
                    $limit_array = get_sub_field('limit_array');
                    $popup_content = get_sub_field('popup_content');
                    echo .$limits;
                endif;
            endwhile;
            echo '<script>jQuery(document).ready(function($){$("body").addClass("limit-popup-on");});</script>';

Sorry for my poor English and thanks for the good plugin.
The above code shows 3 results.

But I want to output last row only.
Anyone can Help me?

• John Huebner

• April 13, 2022 at 1:05 pm

The only way to do this is to know how many rows you have before you begin and then check the row index in the loop

$rows = count(get_field('visits_range'));
while (have_rows('visits_range')) {
   the_row();
   $index = get_row_index();
   if ($index + 1 == $rows) {
     // this is the last row
   }
}

• labzz

• April 14, 2022 at 1:25 am

Thanks for the reply. I solved like below.
I will test above too ! Very thanks.

            $array = array();
            while ( ( have_rows('visits_range', 'option') == 'use') ) : the_row();
                $i=1;
                $usage = get_sub_field('usage');
                $limits = get_sub_field('limits');
                if( get_row_layout() == 'item' && ($usage == 'yes') && ($visits > $limits) ):
                    $array[] = get_sub_field('limits');
                    echo $limits;
                endif;
                $i++;
            endwhile;
            $foo = array_pop($array);