Reply To: Detect if field is hidden by conditional logic

• Nuro

• September 18, 2013 at 8:59 am

You can also name a select field $footer with options yes/no. Then just do a conditional statement based on the $footer value.

<?php

if(get_field('$footer') == "yes")
{
    //...
} else {

   //...
}

?>

or just

<?php if( get_field('$footer') ): ?>
	 //...
<?php endif; ?>

As far as returning null, you can skip the option to show the footer and just check if data has been entered into each of the footer column fields. If no, the field wont show.

<?php 
  
  $col_1 = get_field('$footer_col_1');
  $col_2 = get_field('$footer_col_2');
  $col_3 = get_field('$footer_col_3');

  if($col_1) {
	echo $col_1;
  }

  if($col_2) {
	echo $col_2;
  }

  if($col_3) {
	echo $col_3;
  }

?>

Lots of options, so just go with the method that works best for you.