Reply To: Check if value already exist 2

• John Huebner

• January 16, 2016 at 12:35 pm

Hey, I answered that question and I’ve recently run into the same issue in my own code. The problem is that the global $post does not have a value and there isn’t any way to get the current post id during the ajax call that is validating the field value.

This is a bit complicated.

The first thing that I did was to create a custom field named hidden_post_id, then I created an acf/load_value to add the current post id of the post being edited

add_filter('acf/load_value/name=hidden_post_id', 'add_post_id_as_value'), 10, 3);
function add_post_id_as_value($value, $post_id, $field) {
  return $post_id;
}

The next step was to actually hide this field from the person editing the post. I did this by adding some custom admin CSS

add_action('admin_head', array($this, 'hide_post_id_field'));
function hide_post_id_field() {
  ?>
    <style type="text/css">
      .acf-fields div[data-name="hidden_post_id"] {
        display: none;
      }
    </style>
  <?php 
}

Then you need to alter your validation function to get this value an use it instead of using $post->ID

add_filter('acf/validate_value/name=lien_video', 'validate_lien_video_filter', 10, 4);
function validate_lien_video_filter($valid, $value, $field, $input) {
	$post_id_field_key = 'field_568ad9d81e788';
  if (!$valid || $value == '' || !isset($_POST['acf'][$post_id_field_key])) {
    return $valid;
  }
	// change the field key below to the field key for your 
	// hide_post_id_field field
	$post_id = $_POST['acf'][$post_id_field_key];
  global $post; 
  $args = array(
    'post_type' => 'videos',  // or your post
    'post__not_in' => array($post_id), // do not check this post
    'meta_query' => array(
      array(
        'key' => 'lien_video',
        'value' => $value
      )
    )
  );
  $query = new WP_Query($args);
  if (count($query->posts)) {
    // found at least one post that
    // already has $value
    $valid = 'There is already a post using this video';
  }
  return $valid;
}