Reply To: Getting flexible content sub_fields and making menu from them

• mariol

• January 29, 2015 at 4:58 am

My final code for this issue:

<?php if( have_rows('modules') ): ?> 
<ul>

<?php while ( have_rows('modules') ) : the_row();

if( get_row_layout() == 'photo' ): 

echo '<li>'.the_sub_field('menu_name') . '<li>';

elseif( get_row_layout() == 'text' ): 

echo '<li>' . the_sub_field('menu_name') .'</li>';

endif; endwhile; ?>

</ul>
<?php endif;  // end modules has rows ?>

It works perfectly. Thanks ractoon for your help. It was more easier when i was trying to do it 🙂