Reply To: Get Relationship from another Relationship

• Windurin

• March 11, 2020 at 4:34 am

This is the code I ended up with based on what I assumed the structure should be:

<?php

$items = get_field('add_to_collection');

	if($items) {

		foreach ($items as $i) {

		$artists = get_field('fan_artist', $i->ID);
		$size = 'lisf_thumbnail';
  		
			if($items) {

			$collected_artists= array();

				foreach ($items as $item) {

					if (!is_array($item->ID, $collected_artists)) {
					
					$collected_artists[] = $item->ID;
					
					}
				}
			}
		}
	}

	if ($collected_artists) {

		foreach ($collected_artists as $artist_id) {

		echo get_permalink($artist_id->ID); echo get_the_post_thumbnail($artist_id->ID, $size);

		echo get_permalink($artist_id->ID); echo get_the_title($artist_id->ID); 
		}
	}

?>

I’m sure it’s wrong but I can’t necessarily figure out why. It’s outputting the data for the Collection itself instead of the Fan Artist for one, no matter which return format I use.

Also, I refer directly to the Fan Artist relationship in the $artists variable but don’t repeat it further down, as in your code you have $items/$artist_id

When using the brackets system for if statements etc, it also won’t let me use html within the code. How can I use html with this formatting?

Lastly, I’m getting this PHP warning too:

“Warning: is_array() expects exactly 1 parameter, 2 given in… etc”

I’m sure it’s getting close but, as I say, I just need help with the formatting/structure because I can’t figure it out so I’d really appreciate it if you could post full code for how you think it should be.

Thanks a lot.