I want to display every other row differently. On the odd numbered ones I want the image to display on the right and on the even rows I want the image to display on the left. Heres what I have currently that displays all the rows the same:
if( have_rows('magazines') ): ?>
<? while( have_rows('magazines') ): the_row();
// vars
$name = get_sub_field('magazine_name');
$image = get_sub_field('magazine_image');
$content = get_sub_field('magazine_description');
$link = get_sub_field('magazine_link');
$background = get_sub_field('magazine_background');
?>
<div class="fullscreen background parallax" style="background-image:url('<?php echo $background['url']; ?>');" data-img-width="1600" data-img-height="1064" data-diff="100">
<div class="content-a">
<div class="content-b">
<div class="wrap">
<div class="two-thirds first">
<h1><?php echo $name;?></h1>
<p><?php echo $content;?></p>
<a class="button" href="<?php echo $link;?>">View Magazine</a>
</div>
<div class="one-third">
<img data-name="image" src="<?php echo $image[url];?>" class="magazine-cover" alt="">
</div>
</div>
</div>
</div>
</div>
<?php endwhile; ?>
<?php endif;
Hi @chriswathen
You can use the get_row_index() function to check the current row. It should be something like this:
while( have_rows('magazines') ): the_row();
if( get_row_index() % 2 == 0 ){
// this is an even row
// code to display the image on the left
} else{
// this is an odd row
// code to display the image on the right
}
endwhile;
I hope this helps 🙂
Thank you very much, this is exactly what I was looking for.
